Self-Assessment Quiz: Solving Recurrence Relations

Twenty questions to check your understanding of divide-and-conquer recurrences, the recursion tree, the Master Theorem, merge sort and binary search, and Fibonacci by matrix exponentiation. Answer before opening the key. Aim for 16+.


Question 1

In the divide-and-conquer recurrence $T(n) = a\,T(n/b) + f(n)$, the constant $a$ is:

A) the factor by which the input shrinks B) the number of recursive calls actually made (the branching factor) C) the non-recursive work D) the height of the recursion tree

Question 2

For $T(n) = 8\,T(n/2) + n^2$, the critical exponent $E = \log_b a$ is:

A) $1$ B) $2$ C) $3$ D) $\log_2 8 = 3$, and both C and this are the same

Question 3

The recursion tree for $T(n) = a\,T(n/b) + f(n)$ has height:

A) $\log_a n$ B) $\log_b n$ C) $n/b$ D) $a^{\log_b n}$

Question 4

The number of leaves in that recursion tree equals:

A) $a \cdot b$ B) $\log_b n$ C) $a^{\log_b n} = n^{\log_b a}$ D) $f(n)$

Question 5

Merge sort's recurrence $T(n) = 2\,T(n/2) + \Theta(n)$ falls into which Master-Theorem case, and why?

A) Case 1, because $f(n)$ is polynomially smaller than $n^E$ B) Case 2, because $f(n) = \Theta(n) = \Theta(n^E)$ with $E = 1$ C) Case 3, because $f(n)$ is polynomially larger than $n^E$ D) None — the Master Theorem doesn't apply

Question 6

Binary search's recurrence is $T(n) = T(n/2) + \Theta(1)$. Its solution is:

A) $\Theta(1)$ B) $\Theta(\log n)$ C) $\Theta(n)$ D) $\Theta(n \log n)$

Question 7

Why does binary search have $a = 1$ while merge sort has $a = 2$, even though both halve the input?

A) Binary search is iterative; merge sort is recursive B) Binary search recurses on only one half (throwing the other away); merge sort sorts both halves C) Merge sort halves twice per step D) It is a convention with no real meaning

Question 8

In Master-Theorem Case 3, beyond "$f(n)$ is polynomially larger than $n^E$," you must also verify:

A) the base case is $\Theta(1)$ B) $a$ and $b$ are integers C) the regularity condition $a\,f(n/b) \le c\,f(n)$ for some constant $c < 1$ D) that $f(n)$ is a polynomial

Question 9

For $T(n) = 2\,T(n/2) + n^2$ (Case 3), the solution is:

A) $\Theta(n)$ B) $\Theta(n \log n)$ C) $\Theta(n^2)$ D) $\Theta(n^2 \log n)$

Question 10

The Master Theorem says nothing about $T(n) = 2\,T(n/2) + n\log n$ because:

A) $a$ is not an integer B) the gap between $f(n) = n\log n$ and $n^E = n$ is only logarithmic, not polynomial C) $f(n)$ is smaller than $n^E$ D) the recurrence has no solution

Question 11

The naive recursive Fibonacci runs in time:

A) $\Theta(n)$ B) $\Theta(n \log n)$ C) $\Theta(\phi^n)$, exponential D) $\Theta(\log n)$

Question 12

Why is the naive Fibonacci recurrence $T(n) = T(n-1) + T(n-2) + \Theta(1)$ not solvable by the Master Theorem?

A) It has two subproblems B) The subproblems shrink by subtraction ($n-1$), not division ($n/b$) C) $f(n)$ is constant D) It actually is solvable by the Master Theorem

Question 13

The matrix $M = \begin{pmatrix} 1 & 1 \\ 1 & 0 \end{pmatrix}$ satisfies $M^n = \begin{pmatrix} F_{n+1} & F_n \ F_n & F_{n-1} \end{pmatrix}$. To read off $F_n$ from $M^n$, you take the:

A) determinant B) top-left entry, $F_{n+1}$ C) top-right (or bottom-left) entry, $F_n$ D) trace

Question 14

Computing $F_n$ by matrix exponentiation takes $O(\log n)$ multiplications because:

A) matrix multiplication is fast B) exponentiation by squaring halves the exponent each step, so $\Theta(\log n)$ steps suffice C) Fibonacci numbers grow slowly D) the matrix is only $2 \times 2$

Question 15

The recurrence governing exponentiation by squaring (on the exponent $n$) is:

A) $T(n) = 2\,T(n/2) + \Theta(n)$ B) $T(n) = T(n/2) + \Theta(1)$ — the same as binary search C) $T(n) = T(n-1) + \Theta(1)$ D) $T(n) = n\,T(n-1)$

Question 16 (True/False, justify)

True or false: Binet's closed form $F_n = \frac{\phi^n - \psi^n}{\sqrt 5}$ is the best way to compute $F_n$ exactly for very large $n$. Justify in one sentence.

Question 17 (True/False, justify)

True or false: Merge sort's $\Theta(n\log n)$ bound holds in the best, worst, and average case alike. Justify in one sentence.

Question 18 (True/False, justify)

True or false: "$f(n)$ is larger than $n^E$" is enough to conclude Master-Theorem Case 3. Justify.

Question 19 (Short answer)

State the three-step strategy for applying the Master Theorem to a recurrence $T(n) = a\,T(n/b) + f(n)$.

Question 20 (Short answer)

In one sentence each, name the right tool for: (a) a subtractive recurrence like $T(n) = T(n-1) + \Theta(n)$; (b) a recurrence with *unequal* subproblem sizes like $T(n) = T(n/3) + T(2n/3) + \Theta(n)$.


Answer Key

Q Ans Note
1 B $a$ = recursive calls made; $b$ = shrink factor; $f$ = non-recursive work.
2 D $E = \log_2 8 = 3$ (C and D name the same value).
3 B Input shrinks by $b$ each level, reaching 1 at level $\log_b n$.
4 C $a^i$ nodes at level $i$; at the leaf level $i = \log_b n$, giving $a^{\log_b n} = n^{\log_b a}$.
5 B $E = \log_2 2 = 1$ and $f(n) = \Theta(n) = \Theta(n^E)$ — a tie, Case 2 → $\Theta(n\log n)$.
6 B $a=1, b=2 \Rightarrow E = 0$, $f = \Theta(1) = \Theta(n^0)$, Case 2 → $\Theta(\log n)$.
7 B $a$ counts calls made: binary search recurses once; merge sort recurses twice.
8 C Case 3 requires the regularity condition, not just polynomial dominance.
9 C Case 3 gives $T(n) = \Theta(f(n)) = \Theta(n^2)$ (regularity: $2(n/2)^2 = \tfrac12 n^2$).
10 B $n\log n / n = \log n$ beats no $n^\varepsilon$ → blind spot; true answer $\Theta(n\log^2 n)$.
11 C Its count satisfies a Fibonacci-like recurrence, growing like $F_n = \Theta(\phi^n)$.
12 B Master Theorem needs size $n/b$ (division); this subtracts. Use Chapter 18's methods.
13 C $F_n$ is the off-diagonal entry; $F_{n+1}$ is top-left, $F_{n-1}$ is bottom-right.
14 B Squaring halves the exponent → $\Theta(\log n)$ matrix multiplies (each $\Theta(1)$ here).
15 B Halving the exponent + constant work per step = binary search's recurrence → $\Theta(\log n)$.
16 False $\phi^n$ is irrational; floating-point rounding error grows and eventually gives the wrong integer. Use the integer matrix method.
17 True The split is always into halves and the merge always touches every element once — work is data-independent.
18 False You must also check regularity ($a f(n/b) \le c f(n)$, $c<1$); pathological $f$ can be larger yet violate it.
19 (1) Read off $a, b, f$. (2) Compute $E = \log_b a$ and $n^E$. (3) Compare $f$ to $n^E$ — polynomially smaller (Case 1) / equal (Case 2) / polynomially larger + regularity (Case 3).
20 (a) Characteristic equation / unrolling (Chapter 18); here it unrolls to $\Theta(n^2)$. (b) The Akra–Bazzi method; here it gives $\Theta(n\log n)$.

Topics to review by question

Questions Topic
1–4 The divide-and-conquer form and the recursion tree (§19.1–19.2)
5, 6, 9, 19 Master-Theorem cases and the three-step strategy (§19.3)
7, 17, 20 Merge sort, binary search, and data-independence (§19.4)
8, 18 The regularity condition and Case 3 (§19.3)
10, 12, 20 When the Master Theorem fails (§19.6)
11–14, 16 Fibonacci: naive cost, matrix method, Binet (§19.5)
15 Exponentiation by squaring as a recurrence (§19.5)