Self-Assessment Quiz: Multiple Qubits and Entanglement

Twenty questions on tensor products, Bell states, entanglement, correlations, and what entanglement does and does not let you do. Aim for 16+.


Question 1

A two-qubit system has a state space of dimension:

A) 2 B) 3 C) 4 D) 8

Question 2

The state $\frac{1}{\sqrt2}(|00\rangle + |11\rangle)$ is:

A) A product state B) Entangled C) Mixed D) Unnormalized

Question 3

Which of these two-qubit states is not entangled?

A) $\frac{1}{\sqrt2}(|00\rangle+|11\rangle)$ B) $\frac{1}{\sqrt2}(|01\rangle-|10\rangle)$ C) $\frac{1}{2}(|00\rangle+|01\rangle+|10\rangle+|11\rangle)$ D) $\frac{1}{\sqrt2}(|00\rangle-|11\rangle)$

Question 4

The four Bell states are distinguished from one another by:

A) Their entanglement (some are more entangled) B) Two bits: a relative phase and a parity C) Their normalization D) The number of qubits

Question 5

The Bell state $|\Phi^+\rangle$ is created from $|00\rangle$ by:

A) $H$ on both qubits B) $H$ on qubit 0, then CNOT(0→1) C) CNOT(0→1) then $H$ on qubit 1 D) $X$ on qubit 1

Question 6

Measuring qubit 0 of $|\Phi^+\rangle$ and getting $0$ leaves qubit 1 in:

A) $|0\rangle$ B) $|1\rangle$ C) $|+\rangle$ D) A mixed state

Question 7

The reduced state of one qubit of a Bell pair is:

A) $|0\rangle$ B) $|+\rangle$ C) Maximally mixed D) Undefined

Question 8

That reduced state tells us that a Bell pair's information is:

A) Stored redundantly in each qubit B) Stored entirely in the correlations, not in either qubit locally C) Lost D) Classical

Question 9

Entanglement allows:

A) Faster-than-light signalling B) Correlations stronger than any classical model, but no signalling C) Cloning of unknown states D) Deterministic measurement outcomes

Question 10

The CHSH inequality bounds classical correlations by $|S| \le 2$. Quantum mechanics allows up to:

A) $2$ B) $2\sqrt2 \approx 2.83$ C) $4$ D) Unbounded

Question 11

An experimental CHSH value of $S = 2.4 \pm 0.05$ indicates:

A) An experimental error B) Violation of local realism, with imperfect (noisy) entanglement C) A product state D) Perfect entanglement

Question 12

The GHZ state on three qubits is:

A) $\frac{1}{\sqrt2}(|000\rangle + |111\rangle)$ B) $\frac{1}{\sqrt3}(|001\rangle+|010\rangle+|100\rangle)$ C) $|+\rangle^{\otimes 3}$ D) $\frac{1}{2}(|00\rangle+|11\rangle)^{\otimes 2}$

Question 13

Measuring one qubit of a GHZ state:

A) Leaves the others entangled B) Collapses all three to the same value C) Has no effect D) Produces a Bell state on the remaining two

Question 14

The Schmidt rank of a bipartite pure state is 1 exactly when:

A) The state is maximally entangled B) The state is a product state C) The state is mixed D) Both qubits are measured

Question 15

$n$ qubits require how many complex amplitudes to describe?

A) $2n$ B) $n^2$ C) $2^n$ D) $2^{2n}$

Question 16

True or false: Entanglement can be used to transmit a message faster than light.

Question 17

True or false: Applying a local unitary to one qubit of a Bell pair can destroy the entanglement.

Question 18

True or false: A maximally entangled pair, viewed one qubit at a time, looks exactly like random noise.

Question 19

Short answer. Explain why the reduced state of a Bell-pair qubit being maximally mixed is required by the no-signalling principle.

Question 20

Short answer. Two labs share Bell pairs and observe perfectly correlated outcomes. Why is this not enough to conclude they have beaten classical physics, and what would be?


Answer Key

Q Ans Note
1 C $2^2 = 4$: $|00\rangle,|01\rangle,|10\rangle,|11\rangle$.
2 B It cannot be written as $|a\rangle\otimes|b\rangle$ for any single-qubit states.
3 C $\frac12(|00\rangle+|01\rangle+|10\rangle+|11\rangle) = |+\rangle\otimes|+\rangle$ — it factors. Expanding a product is the standard way this one gets mistaken for entangled.
4 B The four Bell states differ by a bit flip and a phase flip, i.e. two classical bits — the fact that superdense coding exploits (Ch. 10). All four are maximally entangled.
5 B The canonical two-gate recipe.
6 A Perfect correlation: outcome 0 on the first forces $|0\rangle$ on the second.
7 C Tracing out one qubit of a maximally entangled pair gives $I/2$.
8 B Each qubit alone carries nothing; all the information lives in the joint correlations. This is the defining feature of maximal entanglement.
9 B Bell violations prove the correlations exceed any local hidden-variable model, while the no-signalling theorem forbids using them to communicate.
10 B The Tsirelson bound.
11 B Above 2 (so local realism fails) but below $2\sqrt2$ (so the state is not perfectly entangled) — the normal result on real hardware.
12 A The three-qubit "cat state."
13 B GHZ correlations are all-or-nothing: one measurement determines all three, leaving the rest in a product state. Contrast with the W state, which stays entangled.
14 B Schmidt rank 1 ⟺ product state; rank > 1 ⟺ entangled.
15 C The exponential that both enables quantum computing and defeats classical simulation.
16 False Local marginals are unaffected by the distant party's choices; you learn the correlation only after classical communication.
17 False Local unitaries cannot change entanglement — they map Bell states to Bell states. Entanglement is only created or destroyed by interaction (two-qubit gates) or by measurement/decoherence.
18 True The reduced state is maximally mixed — indistinguishable from a fair coin. The structure appears only when the two records are compared.
19 If the reduced state depended on what the distant party did (their basis choice, or whether they measured at all), local statistics would carry that information and signalling would be possible. Maximal mixedness is exactly the condition that no local experiment can detect the remote action.
20 Perfect correlation is trivially reproducible classically — hand each lab a copy of the same random bit. The quantum signature appears only when both labs choose measurement bases at random and the correlations across mismatched bases exceed the CHSH bound of 2. It is the basis-dependence of the correlation, not the correlation itself, that is non-classical.