leftover speed at infinity; $C_3=v_\infty^2$ (Ch. 11)
Read the sign of $\varepsilon$ (the single most useful number)
$\varepsilon$
Semi-major axis
Trajectory
Fate
$\varepsilon < 0$
$a > 0$
circle / ellipse
bound — returns forever
$\varepsilon = 0$
$a \to \infty$
parabola
escapes, arrives at infinity with zero speed
$\varepsilon > 0$
$a < 0$
hyperbola
escapes with speed $v_\infty$ to spare
The threshold concept — higher is slower
Raising an orbit raises its total energy $\varepsilon$ but lowers its speed — the added energy
(and then some) goes into potential energy (height), so kinetic energy (speed) drops.
Virial fingerprint (circular orbits): $KE = -\varepsilon$ and $U = 2\varepsilon$. Push $\varepsilon$ up
toward zero and $KE$ (speed) must fall.
To catch up with a target ahead of you, slow down (burn retrograde → lower, faster, shorter-period
orbit → you gain), then re-raise. To lead, speed up (rise, slow down). On the ground "faster" and "catch
up" are the same; in orbit they are opposites.
Decision aid — "which relation do I use?"
You know…
You want…
Use
$r$ and $a$
speed
vis-viva $v = \sqrt{\mu(2/r - 1/a)}$
$r$ (circular)
speed
$v_{\text{circ}} = \sqrt{\mu/r}$
$v$ and $r$
energy / orbit size
$\varepsilon = v^2/2 - \mu/r$, then $a = -\mu/(2\varepsilon)$
$r_p$ and $r_a$
semi-major axis
$a = (r_p + r_a)/2$
target $v_\infty$, parking radius $r$
injection burn
$\sqrt{v_\infty^2 + 2\mu/r} - \sqrt{\mu/r}$
burn at speed $v$
energy gained
$\Delta\varepsilon = v\,\Delta v + \tfrac12\Delta v^2$ (Oberth: burn where $v$ is large)
Common pitfalls
Pitfall
Reality
Confusing $r$ with $a$ in vis-viva
$r$ is your current distance; $a$ is the orbit's size. Equal only for a circle.
"More energy means more speed."
Higher orbit has more total energy but less speed — energy went into height.
"Escape velocity from LEO is 11.2 km/s."
$11.2$ is from the surface; from LEO, escape is $\approx 10.85$ km/s, only $\approx 3.2$ km/s more than circular.
Fire prograde to catch a target ahead.
That raises your orbit and drops you behind. Burn retrograde to catch up.
Escape first, then burn from high up.
Burning deep in the well (fast) buys more energy per m/s — the Oberth effect. Burn low.
$v_{\text{esc}} = \sqrt{2}\,v_{\text{circ}}$ at any radius.
Escape from LEO $\approx \mathbf{3.2\ \text{km/s}}$; trans-Mars injection from LEO $\approx
\mathbf{3.6\ \text{km/s}}$ (both match the Ch. 3 delta-v map).
On a transfer ellipse (LEO$\to$GEO): $\approx 10.1\ \text{km/s}$ at perigee, $\approx 1.6\ \text{km/s}$
at apogee.
Mission / astrotools additions this chapter
MDR: added your target orbit's Orbital Energy line — $\varepsilon = -\mu/(2a)$, circular speed,
and (if escaping) escape velocity and the parking-orbit-to-escape delta-v.