Library › Rocket Science › Part II: Orbital Mechanics › Chapter 15: The Three-Body Problem and Lagrange Points › Chapter 15 — Key Takeaways (The Three-Body Problem and Lagrange Points)
Chapter 15 — Key Takeaways (The Three-Body Problem and Lagrange Points)
A one-page reference. Reread this before an exam, or before you design a mission to an empty point in space.
The big picture
Add a third gravitating body and the clean two-body world ends: no closed-form solution , and
sensitive dependence on initial conditions (chaos). But when the third body is a massless pebble — the
restricted three-body problem — and you climb into the rotating frame where the two primaries stand
still, five equilibrium points appear:
L4
/ \ L1 L2 L3 — collinear (on the primary line), UNSTABLE
/ \ L4 L5 — triangular (60 deg lead/trail), STABLE if m1/m2 > ~25
m1 --L3-- * ----L1--m2--L2--> * = barycenter
\ /
\ /
L5
Key equations (with symbols and units)
Equation
Gives
Symbols
$\omega^2 = \dfrac{G(m_1+m_2)}{R^3}$
rotating-frame rate (rad/s)
$R$ = primary separation
$\mu^{*} = \dfrac{m_2}{m_1+m_2}$
mass parameter (dimensionless)
not $\mu = GM$; $\to 0$ for lopsided pairs
$\Omega = \tfrac12\omega^2(x^2+y^2) + \dfrac{Gm_1}{r_1} + \dfrac{Gm_2}{r_2}$
effective potential
centrifugal + both gravities
$C_J = 2\Omega - v^2$
Jacobi constant (conserved)
$v$ = speed in the rotating frame
$v^2 = 2\Omega - C_J \geq 0$
zero-velocity curves ($v=0$)
forbids regions where $2\Omega < C_J$
$r_{\text{H}} = R\left(\dfrac{m_2}{3m_1}\right)^{1/3}$
Hill radius = L1/L2 distance from secondary
$\propto m_2^{1/3}$
L4/L5: $\lvert\mathbf{r}-\mathbf{r}_1\rvert=\lvert\mathbf{r}-\mathbf{r}_2\rvert=R$
equilateral point $\Rightarrow \mathbf{g}=-\omega^2\mathbf{r}$
exact, any mass ratio
$\dfrac{m_1}{m_2} > \tfrac12\!\left(25+\sqrt{621}\right)\approx 24.96$
Routh criterion for L4/L5 stability
equivalently $\mu^{*} < 0.0385$
$C_4 = C_5 = 3 - \mu^{*} + \mu^{*2}$
Jacobi value at triangular points (nondim)
$C_1 > C_2 > C_3 > C_4$
The five points at a glance
Point
Where
Stable?
Used by / for
L1
between primaries, near secondary
No (saddle)
SOHO, ACE, DSCOVR — Sun-watch, solar-wind warning
L2
beyond secondary (anti-primary)
No (saddle)
JWST, Gaia, Planck — cold IR observatories; EM-L2 far-side relay
L3
beyond primary (opposite secondary)
No (saddle)
~1 AU behind the Sun; no major missions
L4
$60^\circ$ ahead of secondary
Yes if $m_1/m_2>25$
Jupiter Trojans (Greek camp); Lucy
L5
$60^\circ$ behind secondary
Yes if $m_1/m_2>25$
Jupiter Trojans (Trojan camp)
Worked anchors (memorize the shape, not the digits)
Quantity
Value
Where
Sun–Earth L1/L2 distance from Earth
$\approx 1.5\times10^6\ \text{km}$ ($\sim 4$ lunar dist., $1\%$ AU)
§15.3
Earth–Moon L1/L2 distance from Moon
$\approx 61{,}500\ \text{km}$ ($16\%$ of EM dist.)
§15.3
L4/L5 lead/trail angle
$60^\circ$; distance $R$ from both primaries
§15.3
Collinear instability $e$-folding (Sun–Earth)
$\sim 23$ days
§15.4
Libration station-keeping
$\sim$ few m/s/yr (Sun–Earth); $\sim 20$ m/s/yr (Earth–Moon)
§15.4
Routh threshold
$m_1/m_2 \approx 24.96$
§15.4
Decision aid — "which idea when?"
You know…
You want…
Use
$m_1, m_2, R$
L1/L2 distance from secondary
Hill radius $R(m_2/3m_1)^{1/3}$
mass ratio $m_1/m_2$
are L4/L5 stable?
compare to $24.96$ (Routh)
position + velocity (rotating frame)
a conserved check
Jacobi constant $2\Omega - v^2$
a cold telescope needs one sunshield
which point?
L2 (Sun, Earth, Moon all one side)
continuous Sun view / space-weather warning
which point?
L1 (upstream of Earth)
minimum fuel, time to spare
how to transfer?
low-energy / weak-stability-boundary route
far-side lunar comm
where to relay?
Earth–Moon L2 halo
Common pitfalls
Pitfall
Reality
"A Lagrange point is where gravity cancels (zero-g)."
Gravity does not cancel; forces balance in the rotating frame . Net gravity supplies the centripetal force for co-rotation.
"L4/L5 are potential maxima, so they must be unstable."
The Coriolis force (absent from a static picture) curves a runaway into a stable loop — stable if $m_1/m_2>25$.
"Instability makes L1/L2 useless for missions."
Drift is slow and predictable; halo + a few m/s/yr keeps a flagship there for decades.
"You can park on a Lagrange point."
You orbit around it in a halo — to stay off the unstable point and out of eclipse / solar glare.
"The Hill sphere and sphere of influence are the same."
Cousins, different exponents: SOI $\propto (m_2/m_1)^{2/5}$; Hill $\propto (m_2/m_1)^{1/3}$. Earth: $924{,}000$ vs $1.5\times10^6$ km.
"The superhighway is free."
Free in fuel , expensive in time (months–years); needs the right geometry.
Numbers worth memorizing
Sun–Earth L1/L2: $\approx 1.5\times10^6\ \text{km}$ from Earth ($\sim 4$ lunar distances).
Exactly five Lagrange points; L4/L5 at $60^\circ$; L4/L5 stable when $m_1/m_2 > \approx 25$.
Hill radius $\propto m_2^{1/3}$; collinear points are unstable, triangular can be stable.
Only one conserved quantity survives (the Jacobi constant); low-energy transfers trade time for fuel.
MDR: added the "Multi-body dynamics" note — does the mission use a Lagrange point (relay, staging,
ballistic capture, Trojan target), or, if not, why not . Track B may add an Earth–Moon L2 relay and its
station-keeping line; Track D may target a Trojan.
Code (optional, non-canonical helper): collinear_hill_distance(m1, m2, R) and
triangular_point(R, mu_star, leading) locate the five points for any system. No canonical astrotools
module is assigned this chapter.
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Further Reading: The Three-Body Problem and Lagrange Points