Self-Assessment Quiz: Energy in Space — The Vis-Viva Equation
Twenty questions to check your grasp of orbital energy, the vis-viva equation, escape, and the "higher-is-slower" paradox. Answer each before opening the key. Aim for 16 or more. Use $\mu_\oplus = 3.986\times10^{5}\ \text{km}^3/\text{s}^2$ and $R_\oplus = 6{,}371\ \text{km}$.
Question 1
The specific orbital energy $\varepsilon = \tfrac{v^2}{2} - \tfrac{\mu}{r}$ of a coasting spacecraft is:
A) always positive B) constant (conserved) as it coasts around its orbit C) larger for a heavier spacecraft in the same orbit D) equal to its kinetic energy
Question 2
The vis-viva equation $v^2 = \mu\left(\tfrac{2}{r} - \tfrac{1}{a}\right)$ gives you:
A) the orbital period B) the speed at any point on any orbit C) the escape velocity and nothing else D) the mass ratio of the rocket
Question 3
For any bound orbit (a closed ellipse or circle), the specific orbital energy is:
A) positive B) zero C) negative D) infinite
Question 4
Compared with a lower circular orbit, a higher circular orbit has:
A) higher speed B) lower speed C) exactly the same speed D) zero speed
Question 5
The circular orbital velocity at radius $r$ is:
A) $\sqrt{2\mu/r}$ B) $\sqrt{\mu/r}$ C) $\mu/r$ D) $\sqrt{\mu/(2r)}$
Question 6
Escape velocity at a given radius equals the circular velocity there multiplied by:
A) $2$ B) $\sqrt{2}$ C) $\tfrac{1}{2}$ D) $\pi$
Question 7
A parabolic (marginal-escape) trajectory has a specific orbital energy of:
A) less than zero B) exactly zero C) greater than zero D) undefined
Question 8
A hyperbolic trajectory has a semi-major axis $a$ that is:
A) positive B) zero C) negative D) always equal to $r$
Question 9
In $\varepsilon = -\mu/(2a)$, an orbit with a larger semi-major axis has:
A) lower (more negative) energy B) higher (less negative) energy C) exactly zero energy D) positive energy in every case
Question 10
To catch up with a target that is ahead of you in the same circular orbit, you should burn:
A) prograde (toward the target) B) retrograde (away from the target) C) straight up (radially outward) D) not at all — you will drift into it
Question 11
The orbital speed in a $400\ \text{km}$ circular LEO is about:
A) $3.1\ \text{km/s}$ B) $7.7\ \text{km/s}$ C) $11.2\ \text{km/s}$ D) $27\ \text{km/s}$
Question 12
The orbital speed in geostationary orbit (GEO) is about:
A) $3.1\ \text{km/s}$ B) $7.7\ \text{km/s}$ C) $11.2\ \text{km/s}$ D) $1.0\ \text{km/s}$
Question 13
On an elliptical orbit, the spacecraft moves fastest at:
A) apoapsis (the highest point) B) periapsis (the lowest point) C) the midpoint of the ellipse D) nowhere — the speed is constant
Question 14
In the vis-viva equation, the symbol $r$ stands for:
A) the semi-major axis of the orbit B) the spacecraft's current distance from the center of the body C) the periapsis distance, always D) the radius of the planet
Question 15 (True/False, justify)
"Raising a satellite to a higher orbit increases both its energy and its speed." True or false? Justify in one sentence.
Question 16 (True/False, justify)
"A spacecraft's specific orbital energy $\varepsilon$ depends on the spacecraft's mass." True or false? Explain briefly.
Question 17 (True/False, justify)
"Escape velocity from a $400\ \text{km}$ low Earth orbit is about $11.2\ \text{km/s}$." True or false? Say what is right and what is wrong about the statement.
Question 18 (Short answer)
A satellite is in a circular orbit at $r = 6{,}771\ \text{km}$. Compute (a) its circular speed and (b) its specific orbital energy $\varepsilon$ in $\text{MJ/kg}$. Show the two calculations.
Question 19 (Short answer)
Explain, in two sentences, why firing prograde (speeding up your instantaneous velocity) leaves you in an orbit where you ultimately move slower. Refer to where the added energy goes.
Question 20 (Short answer)
State this chapter's threshold concept in your own words, and give one practical consequence of it for flying a rendezvous.
Answer Key
| Q | Ans | Note |
|---|---|---|
| 1 | B | $\varepsilon$ is conserved during coasting; it is per-unit-mass, so it does not depend on the craft's mass. |
| 2 | B | Vis-viva returns the speed from just $r$ and $a$. |
| 3 | C | Bound orbits cannot reach infinity, so total energy is negative. |
| 4 | B | Higher orbit → slower ($v_{\text{circ}} = \sqrt{\mu/r}$ decreases with $r$). |
| 5 | B | $v_{\text{circ}} = \sqrt{\mu/r}$ from balancing gravity and centripetal acceleration. |
| 6 | B | $v_{\text{esc}} = \sqrt{2\mu/r} = \sqrt{2}\,v_{\text{circ}}$. |
| 7 | B | Parabolic escape is the $\varepsilon = 0$ boundary. |
| 8 | C | $\varepsilon > 0$ forces $a = -\mu/(2\varepsilon) < 0$. |
| 9 | B | $\varepsilon = -\mu/(2a)$: larger $a$ → less negative (higher) energy. |
| 10 | B | Burn retrograde → lower, faster, shorter-period orbit → you catch up. |
| 11 | B | $\sqrt{\mu/6771} \approx 7.67\ \text{km/s}$. |
| 12 | A | $\sqrt{\mu/42164} \approx 3.07\ \text{km/s}$. |
| 13 | B | Deepest in the well → most kinetic energy → fastest at periapsis. |
| 14 | B | $r$ is the current distance; $a$ is the orbit's size. They coincide only for a circle. |
| 15 | False | Energy rises, but speed falls — the added energy (and more) goes into potential energy as the craft climbs higher. |
| 16 | False | $\varepsilon$ is energy per unit mass; the mass cancels, so it is a property of the orbit, not the vehicle. |
| 17 | False | $11.2\ \text{km/s}$ is escape from the surface. At $400\ \text{km}$, escape velocity is $\approx 10.85\ \text{km/s}$, and only $\approx 3.2\ \text{km/s}$ more than the LEO circular speed. |
| 18 | — | (a) $v = \sqrt{398600/6771} = 7.67\ \text{km/s}$. (b) $\varepsilon = -398600/(2\times6771) = -29.4\ \text{MJ/kg}$. |
| 19 | — | The prograde burn raises the total energy $\varepsilon$, which enlarges the orbit ($a$ grows); a bigger orbit is slower because the added energy is stored as potential energy (height), while kinetic energy (speed) actually decreases. |
| 20 | — | "A higher orbit is a slower orbit — to speed up (shorten your period) you must slow down (drop lower)." Consequence: to rendezvous with a target ahead, burn retrograde to drop into a lower, faster orbit and catch up, then raise back to it. |
Topics to review by question
| Questions | Topic | Section |
|---|---|---|
| 1, 3, 16, 18 | Specific orbital energy | §6.1–6.2 |
| 2, 13, 14 | The vis-viva equation | §6.3 |
| 4, 5, 9, 11, 12 | Circular velocity & orbit size | §6.1, §6.2 |
| 6, 7, 8, 17 | Escape, parabolic, hyperbolic | §6.5 |
| 10, 15, 19, 20 | Higher-is-slower / the paradox | §6.4, §6.6 |